5y^4-1y^2+1.5=0

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Solution for 5y^4-1y^2+1.5=0 equation:


Simplifying
5y4 + -1y2 + 1.5 = 0

Reorder the terms:
1.5 + -1y2 + 5y4 = 0

Solving
1.5 + -1y2 + 5y4 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.3 + -0.2y2 + y4 = 0

Move the constant term to the right:

Add '-0.3' to each side of the equation.
0.3 + -0.2y2 + -0.3 + y4 = 0 + -0.3

Reorder the terms:
0.3 + -0.3 + -0.2y2 + y4 = 0 + -0.3

Combine like terms: 0.3 + -0.3 = 0.0
0.0 + -0.2y2 + y4 = 0 + -0.3
-0.2y2 + y4 = 0 + -0.3

Combine like terms: 0 + -0.3 = -0.3
-0.2y2 + y4 = -0.3

The y term is -0.2y2.  Take half its coefficient (-0.1).
Square it (0.01) and add it to both sides.

Add '0.01' to each side of the equation.
-0.2y2 + 0.01 + y4 = -0.3 + 0.01

Reorder the terms:
0.01 + -0.2y2 + y4 = -0.3 + 0.01

Combine like terms: -0.3 + 0.01 = -0.29
0.01 + -0.2y2 + y4 = -0.29

Factor a perfect square on the left side:
(y2 + -0.1)(y2 + -0.1) = -0.29

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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